Nickolay Kudasov | 21 Sep 00:23 2013

Demarcating monad transformers.

Hi Café,

Below I describe what I call «demarcating monad transformer». It works great for my purposes, though the construction feels a bit awkward.
Perhaps, this is just an instance of a general case. For details and example, see [1] (single module package).

Recently I got a challenge of manipulating transformed monadic values. In my case the value was of type t (Free f) a (or MonadFree m => t m a).
The challange itself was to provide a function:

transform :: (Functor f, MonadTrans t) => (forall b. f b -> t (Free f) b) -> t (Free f) a -> t (Free f) a

The type t (Free f) a for my purposes can be read as «a program with low-level API specified with functor f and extra features specified with monad transformer t».
transform takes a “basic transformation” phi and an abstract program p and applies phi whenever p “executes” command of free functor f.

It turns out that this function is impossible (try StateT). The point is that you can't “get inside” of transformed monadic value.

So I came up with idea of «demarcating» monad transformer. By «demarcating» I mean separating pure monadic computations (lifted m a) from transformed ones (t m a).

Such separation can be made explicit with the help of free monads:

data DemarcateF t m next = forall b. DemarcateMonad (m b) (b -> next) -- "pure" monadic computation | forall b. DemarcateTrans (t m b) (b -> next) -- transformed monadic computation instance Functor (Demarcate t m) where ... -- getting monad for free newtype Demarcate t m a = Demarcate { unDemarcate :: Free (DemarcateF t m) a } instance Monad (Demarcate t m) where ... instance MonadTrans (Demarcate t) where ...

With that I can define transform functions:

-- transform arbitrary monadic computation transformDemarcateM :: (forall b. m b -> Demarcate t m b) -> Demarcate t m a -> Demarcate t m a -- transform free monadic actions transformDemarcateFree :: (forall b. f b -> Demarcate t (Free f) b) -> Demarcate t (Free f) a -> Demarcate t (Free f) a transformDemarcateFree phi = transformDemarcateM (iterM phi)

The complete code is available at [1]. Check out examples/simple.hs for a use case.

Now the questions are:

  • has anyone else encountered such a challenge?
  • is this solution an instance of a more general pattern?
  • is it sensible to use Demarcate t m a when m is not a free monad?
  • how Demarcate may affect the performance?

Thanks in advance,


Haskell-Cafe mailing list
Haskell-Cafe <at>