Hello. I am looking for a substring replacement based on Perl like regular expressions that would let me use part of the original string in the replacement string. Something like: reReplace "name is (.*)\\." "hi \1!" "my name is john." which would result in "hy john!" Any help? Romildo
Hi Romildo. On Sat, Aug 18, 2012 at 9:18 AM, José Romildo Malaquias <j.romildo <at> gmail.com> wrote: (...) > I am looking for a substring replacement based on Perl like regular > expressions that would let me use part of the original string in the > replacement string. Something like: > > reReplace "name is (.*)\\." "hi \1!" "my name is john." > > which would result in > > "hy john!" It's not exactly what you're looking for, but I'd simply do something like this, using Text.Regex.TDFA or any other: let [[_, name]] = "my name is john." =~ "name is (.*)\\." in "hi " ++ name ++ "!" Greetings. (...) -- -- marcot http://marcot.eti.br/ _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe <at> haskell.org(Continue reading)
On Sat, Aug 18, 2012 at 09:39:01AM -0300, Marco Túlio Pimenta Gontijo wrote: > Hi Romildo. > > On Sat, Aug 18, 2012 at 9:18 AM, José Romildo Malaquias <j.romildo <at> gmail.com> > wrote: > (...) > > I am looking for a substring replacement based on Perl like regular > > expressions that would let me use part of the original string in the > > replacement string. Something like: > > > > reReplace "name is (.*)\\." "hi \1!" "my name is john." > > > > which would result in > > > > "hy john!" > > It's not exactly what you're looking for, but I'd simply do something like this, > using Text.Regex.TDFA or any other: > > let [[_, name]] = "my name is john." =~ "name is (.*)\\." in "hi " ++ > name ++ "!" Thanks for the tip. It was useful to solve my original problem. Romildo
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